1/4y^2=y-1

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Solution for 1/4y^2=y-1 equation: 


y in (-oo:+oo)

(1/4)*y^2 = y-1 // - y-1

(1/4)*y^2-y+1 = 0

1/4*y^2-y+1 = 0

DELTA = (-1)^2-(1/4*1*4)

DELTA = 0

y = 1/(1/4*2)

y = 2 or y = 2

y in { 2, 2 }

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